One-dimensional arrays A and B both contain 10 numbers. Build an array C, each element of which is calculated using the formula:

Block-schemes of the solution:

C++ implementation:

#include<iostream> #include<time.h> #include<conio.h>//for getch() using namespace std; int n = 10;//array size bool flag = 1; void random(int*a, int*b)//generate array of random numbers { for (int k = 0; k<n; k++) { a[k] = rand() % 100;//from 0 to 99 b[k] = rand() % 100; } } void input(int*a, int*b)//input arrays manually { for (int k = 0; k<n; k++) { cout << "a[" << k << "]="; cin >> a[k]; cout << "b[" << k << "]="; cin >> b[k]; } } void calc(int*a, int*b, float*c)//calculate array c[] { for (int k = 0; k<n; k++) c[k] = (a[k] == b[k]) ? 1 : 1 / ((float)a[k] - (float)b[k]);//if a==b, c=1; else c=1/(a-b) } void output(int*a, int*b, float*c)//output a[], b[], c[](result) { for (int k = 0; k<n; k++) cout << "a[" << k << "]=" << a[k] << '\t' << "b[" << k << "]=" << b[k] << '\t' << "c[" << k << "]=" << c[k] << endl; } void main() { srand(time(0));//for random() int *a = new int[n];//dynamic array int *b = new int[n];//dynamic array float *c = new float[n];//dynamic result array int key;//switcher do { cout << "1. enter\n2. random\n"; key = _getch(); switch (key)//switching { case '1': input(a, b); flag = 0; break;//manual input case '2': random(a, b); flag = 0; break;//random input default: cout << "you entered other number" << endl; } } while (flag); calc(a, b, c); //calculate third massive output(a, b, c); //output three massives system("pause");//pause console }

Screenshots:

Manual input

Random input

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