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Write a Python 3 code for this method.<\/p>\n
Solution<\/strong><\/p>\n Hand solution<\/p>\n Let\u2019s choose the initial values of x<\/em>:<\/p>\n Plugging the above values into the equation, we get:<\/p>\n The formula for finding the next x<\/em> values is:<\/p>\n Now, we can find the<\/p>\n <\/p>\n <\/span> <\/span> <\/em><\/p>\n value:<\/p>\n Changing x<\/em> for the<\/p>\n <\/p>\n <\/span> <\/span> <\/em><\/p>\n value:<\/p>\n Repeating the above steps, we will find the next x<\/em> values:<\/p>\n <\/p>\n is the root of the equation.<\/p>\n Python 3 Code<\/strong><\/p>\n Let\u2019s define a function for our equation first:<\/p>\n Now, it\u2019s time to write our main function for finding the root of the equation. As we should choose two initial values for x, our function should accept two initial parameters:<\/p>\n At last, the found x<\/em> value is returned:<\/p>\n The entire code:<\/p>\n<\/a><\/p>\n<\/a><\/p>\n<\/a><\/p>\n<\/p>\n<\/a><\/p>\n<\/p>\n<\/a><\/p>\n<\/a><\/p>\n<\/a><\/p>\n<\/a><\/p>\n<\/a><\/p>\n<\/a>
\nKnowing the formula for finding the next values of x<\/em>, we can write a function for it too:<\/p>\n<\/a><\/p>\n<\/a>
\nNow, let\u2019s find the corresponding y<\/em> values:<\/p>\n<\/a>
\nTo simplify things, we will use current<\/em> and previous<\/em> values (xc, yc, xp, yp<\/em>):<\/p>\n<\/a>
\nAnd let\u2019s repeat the above steps in a while<\/em> loop. In order to prevent an infinite loop, we need to add an exit condition. In our case we will check if the absolute value of y is larger than the 0.001<\/strong> threshold:<\/p>\n<\/a><\/p>\n<\/a><\/p>\n<\/a><\/p>\n<\/a><\/p>\n