![\"bisection](\"https:\/\/assignmentshark.com\/blog\/wp-content\/uploads\/2019\/08\/1-1.png\")
<\/a><\/p>\n<\/p>\n
Write a Python 3 code for this method.<\/p>\n
Solution<\/strong><\/p>\n Hand Solution<\/p>\n Let\u2019s choose the initial values of x<\/em> so that<\/p>\n have different signs:<\/p>\n Plugging the above values into the equation, we get:<\/p>\n The next value of x is:<\/p>\n <\/span> <\/span> value into the equation:<\/p>\n As the signs of<\/p>\n are the same, we will replace the x0 value with x2 and repeat the above steps:<\/p>\n Now, we will replace the x1<\/em> value with x2<\/em>, as the signs of<\/p>\n are the same:<\/p>\n As<\/p>\n the root of the equation is approximately equal to 1.89282.<\/strong><\/p>\n Python 3 Code<\/p>\n Let\u2019s define a function for our equation first:<\/p>\n Now, we will write a function for defining the sign:<\/p>\n This is our main function for finding the root of the equation. As we must choose two initial values for x, our function should accept two initial parameters:<\/p>\n For simplification:<\/p>\n And let\u2019s repeat the above steps in a while<\/em> loop. In order to prevent infinite loop, it\u2019s important to add an exit condition. In our case we will check if the absolute value of y is larger than the 0.001<\/strong> threshold. To decide what x value should be replaced, the sign check statement will be written as follows:<\/p>\n The entire code:<\/p>\n<\/a><\/p>\n<\/a><\/p>\n<\/a><\/p>\n<\/a>
\nThen we will plug the<\/p>\n<\/p>\n<\/a><\/p>\n<\/a><\/p>\n<\/a><\/p>\n<\/a><\/p>\n<\/a><\/p>\n<\/a><\/a><\/p>\n<\/a><\/p>\n<\/a><\/p>\n<\/a><\/p>\n<\/a><\/p>\n<\/a><\/p>\n<\/a><\/p>\n<\/a><\/p>\n<\/a><\/p>\n<\/a>At last, the found x<\/em> value is returned:<\/p>\n<\/a><\/p>\n<\/a><\/p>\n<\/a><\/p>\n